in one round of N days(N>=3 for obvious reason)
(N-3)* 0.01 + 1
where N >=3 belongs to natural number
assume m is the answer
then ((m-3)*0.01 + 1)^n >= ((n-3)*0.01 +1)^m
n*log((m-3)* 0.01 + 1) >= m * log((n-3)*0.01 + 1)
m, n belongs to natural number and >=3
just solve the equation and u will get the answer